-7x^2+18x-8=0

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Solution for -7x^2+18x-8=0 equation:



-7x^2+18x-8=0
a = -7; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·(-7)·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10}{2*-7}=\frac{-28}{-14} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10}{2*-7}=\frac{-8}{-14} =4/7 $

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